0=(6b*b*b)-b^2-24b+4

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Solution for 0=(6b*b*b)-b^2-24b+4 equation: 



0=(6b*b*b)-b^2-24b+4

We move all terms to the left:

0-((6b*b*b)-b^2-24b+4)=0

We add all the numbers together, and all the variables

-((+6b*b*b)-b^2-24b+4)+0=0

We add all the numbers together, and all the variables

-((+6b*b*b)-b^2-24b+4)=0



We calculate terms in parentheses: -((+6b*b*b)-b^2-24b+4), so:

(+6b*b*b)-b^2-24b+4

determiningTheFunctionDomain
-b^2+(+6b*b*b)-24b+4

We add all the numbers together, and all the variables

-1b^2-24b+(+6b*b*b)+4

We get rid of parentheses

-1b^2-24b+6b*b*b+4

Wy multiply elements

-1b^2+6b^3*b-24b+4

We do not support ebpression: b^3

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